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2400-6x^2=0
a = -6; b = 0; c = +2400;
Δ = b2-4ac
Δ = 02-4·(-6)·2400
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{57600}=240$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240}{2*-6}=\frac{-240}{-12} =+20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240}{2*-6}=\frac{240}{-12} =-20 $
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